00:01
Hi, here in this given problem, resistance of resistance connected to the ac generator that is given as r is equal to 3 .33 kilo -oam and the voltage produced, the maximum voltage produced, the peak voltage produced by this generator 141 volt.
00:37
In the first part of the problem, we have to find average power produced by this ac generator.
00:46
That will be given by vrmsa square by impedance and as there is only resistance connected to this generator.
00:55
So impedance will be equal to resistance and multiplied by cos -5 which is the power factor.
01:01
And for r only we know power factor is equal to 1.
01:10
So for vrms that will be given by peak voltage, maximum voltage, v0, divided by root 2, having a square of it and 1 upon our.
01:24
So plugging in the known values, this is 1 by 3 .33 kilo, kilo, or multiplied by 1.
01:32
1000 multiplied by for v0 that is 141 divided by root 2 and having a square of it...