00:03
In this problem, the concept covered is the newton's second law of motion and the newton's third law of motion.
00:10
The girl exert the force on the rope, then the same amount of force is exerted by the rope on the curve.
00:17
So for part a, we need to draw the freeboard diagram for the sledge, and this is the sledge, and the force on the slays is along the positive x direction, and that is f, and the other force is the weight of the sledge, ejecting vertical downward that is m1 g and the reaction from the ground that is n1 and let's say the acceleration of the sledge is along the horizontal direction and that is a sledge.
00:51
So from newton's second law of motion we can write f is equivalent to the mass of the sledge into the acceleration of the sledge or the acceleration of the sledge is the force that is 5 .2 newton's upon the mass of the sledge that is 8 .4 kilogram.
01:17
So the acceleration of the sledge is 0 .62 meters per second square.
01:28
Now part b in this part we need to draw the free bird diagram of the curve and the force exerted on the girl by the rope is along the negative x direction and that is of the same magnitude okay so from the newton second law of motion we can write the acceleration of the girl is equivalent to the force that is minus 5 .2 newton upon 8 .4 or sorry upon the mass of the girl and that is 40 kg or the acceleration of the girl is minus 0 .13 meters for second square and the magnitude of the acceleration is 0 .13 meters per second square.
02:33
Now part c...