00:01
In this problem, we're going to talk about several topics concerning one -dimensional motion.
00:06
So let's say that we have a particle that is undergoing one -dimensional motion, where the x -coronid is given by a certain function x of t.
00:18
Then we can calculate the velocity of that particle as d x d t, the acceleration as dv -tt, or d t.
00:31
2x d t2 that is the second derivative of x also the force applied on that object is equal to the mass of the object times the acceleration the kinetic energy of that object is the mass times v squared over 2 and also we need to know that the power is the derivative of the energy with respect to time.
01:11
Okay, so these are the concepts we're going to use in our problem.
01:15
So basically, what we have is an object that has a mass of four kilograms that is traveling with a trajectory that is given by a function x of t, that is equal to t plus 2t, q.
01:35
And in question a, our goal is to find the kinetic energy of the time, particle as a function of t so what i'm going to do first is to calculate v and v is d x d t so it's the derivative of t plus two t cubed the derivative of t is one the derivative of t cubed is three t squared so three times two six so uh the kinetic energy is the mass times v squared over two the mass is four then we divide it by 4 and multiply it by 1 plus 6 t squared squared.
02:21
So the kinetic energy is 2 times 1 plus 6 t squared squared in joules.
02:36
In question b, we have to calculate both the force and the acceleration on that object.
02:46
Let's start with the acceleration.
02:48
Now we know that the acceleration is a derivative of the velocity with respect to 10.
02:52
The velocity is 1 plus 6 t squared.
03:00
The derivative of 1 is 0.
03:03
The derivative of t squared is 2t.
03:06
So the acceleration is 12 t.
03:09
And the force is just the mass times the acceleration.
03:14
So it's 4 kilograms times 12t, so that's 48 t joules...