00:01
So we've got a wire.
00:04
So i'm going to draw the wire.
00:07
It's 50 centimeters long.
00:10
I'm going to draw it with its first harmonic.
00:21
Its mass is 0 .0010 kilograms, and its tension is 440 newons.
00:36
Um, mu equals m over l, and v equals the square root of t over mu.
00:54
So let's keep reading.
00:58
Open end of an open, closed tube of air.
01:02
So we got a tube of air here.
01:05
It's open, closed.
01:12
Okay.
01:20
So fundamental frequency.
01:24
Is going to be v over 2l, which is the square root of t over mu times 1 over 2l, but mu is m is m over l.
01:55
So this is going to be the square root of t l over m.
02:06
It's supposed to be lowercase m times one over two l which if we simplify it more is going to be one half square root of t over lm lowercase m okay we're looking for the length of the tube that gives us the fundamental frequency in the tube.
02:54
So the fundamental frequency in the tube is v over 2l, two length of tube.
03:09
Oh, wait a minute...