00:01
This is question 34 from chapter 13, and we have 50 grams of impure kclo3, contaminated with 10 % of potassium chloride.
00:14
So we have to calculate the minimum quantity of water to dissolve all the kcl from the sample.
00:26
Okay, so the first thing we'll do is actually find the mass of kcls.
00:33
So the kcl mass.
00:41
They give us, we have 10 % of it, so it will be 10 times, and it says we have 50 grams of impure.
00:53
It says we 10 times 50 per 100.
01:07
And this is going to come out to be 5 grams.
01:18
Okay.
01:19
So that is the mass of water to dissolve 5 grams of kcl and now we are going to set that up to see how much water needs to be dissolved.
01:34
So we're going to set up 25 .5 from the kcl over 100 is equal to the 5 grams over x.
01:52
So we are solving for x.
01:57
That means how much water needs to dissolve and that is going to to come out to be 19 .61 grams.
02:15
So this is for dissolving the water...