00:01
So in this question, we have given height of the object h .o.
00:04
Equals to 5 .00 cm and object is placed at a distance, do8 is equals to 30 .0 0 .0 cm from a convex mirror.
00:14
We have given convex mirror of focal length, capital, small f.
00:19
This is equal to minus 10 .0 centimeter.
00:23
So we have to determine here the size orientation of the size of the size.
00:30
Orientation and position of image and position of image.
00:39
We can determine first of all the position.
00:42
So we're using mirror formula.
00:43
So we can write that 1 by do plus 1 by d .i, do is the object distance.
00:49
D .i is the image distance.
00:51
This is equals to 1 by f.
00:53
So substituting values.
00:54
So 1 by 30 .0 plus 1 by d .i, this is equals to 1 by minus 10 .0.
01:01
So from here after solving, we will get d .i.
01:04
This is equals to minus 7 .50 centimeters.
01:09
So this is the position of the image.
01:12
Okay.
01:13
Now, we can calculate the image height.
01:16
So image height will be given by magnification.
01:19
So magnification, it is equals to minus d .i by d .o.
01:23
And it is also given by h .i.
01:26
Okay...