00:01
So for this question, we're asked to solve the specific heat of the element.
00:07
So 1009 grams of ice is melted in this problem, and we need to convert the mass into molar mass.
00:16
So in order to do that, we use mass divided by the molar mass.
00:21
So 109 .5, divided by bt, which is the molar mass of water, will eventually get.
00:33
Get 6 .08 moles of water melted.
00:41
We know that 6 .08 moles is melted, then we have to calculate heat absorbed by the ice, which is the heat of fusion times the mole of water.
00:51
The heat of fusion you can find in the table is 6 .02 kilojoules per mole times the 6 .08, which will get 36 .62 kilojoules with that value, we can now calculate the specific heat of the element...