00:01
In this problem, it is given that stopping distance is 121 feet.
00:12
If initial speed is 60 mile per hour.
00:24
And if speed is 80 mile per hour, stopping distance is 211 feet.
00:35
So we will have to find the average braking acceleration.
00:40
So firstly we will need to change feet into mile.
00:46
If we change to 11 feet to mile, it is around 0 .0399 mile and 121 feet is around 1 .0229 mile.
01:04
So the part a, we will use kinematic equation v final is equal to v initial.
01:14
Plus a into t is the acceleration and t is the time but here time is not given so we will not use this we will use v final square v initial square plus 2a into s because this is given here a is equal to v final square minus v initial square divided by twice of s one v final is zero because after braking car will stop and we initially 60 mile per hour whole square and divided by 2 into s 1 is 0 .0229.
02:00
Exclamation will be equal to minus 78602 mile per hour square we need to change it into mile per hour per second so we will divide this by 3600 so this will be equal to minus 21 .8 mile per hour per second and meter per second if we change this, so this will be equal to minus 9 .76 meter per second square.
02:38
We will use the same method for the part b also...