00:01
This question is about a bungee cord, and i know that a bungee cord acts like a spring.
00:08
Force equals kx, where x is the stretch.
00:22
Now, we are told that mu, basically, is 0 .075 kilograms.
00:37
Per 1 .20 meters.
00:45
So that is our linear density.
00:51
I'm also going to use, i'm going to write down that l original is 1 .20 meters, but it's stretched to 1 .8 meters.
01:09
So that means that the stretch, would be 1 .8 minus 1 .2, which would be 0 .60 meters.
01:25
And so the final length would be l plus x, which is the 1 .8.
01:34
So this length is vibrated at a frequency of 20 hertz, and it produces, a standing wave with two antinodes.
01:53
So i'm gonna draw two antinodes here with the vibration in here.
02:11
Okay, that's showing me that the mode is, so the fundamental frequency is just going to be half of the 20.
02:40
And it goes two right here.
02:43
Going to be 10 hertz.
02:47
And i could actually write f sub 2 here because we know it's the second harmonic.
02:55
All right.
02:59
The fundamental frequency is v over to l, where l in this case is actually l plus x.
03:13
It's the length when it's vibrating.
03:18
V is going to be the square root of t over mu.
03:28
We know what mu is, but t would be opposing the stretching force...