Question
A "75 -watt" lightbulb uses an average power of 75 $\mathrm{w}$ when connected to an rms voltage of 120 $\mathrm{V}$ . (a) What is the resistance of thelightbulb? (b) What is the maximum current in the bulb? (c) Whatis the maximum power used by the bulb at any given instant of time?
Step 1
We can use the formula for power, which is $P = \frac{V_{rms}^2}{R}$, where $P$ is the power, $V_{rms}$ is the rms voltage, and $R$ is the resistance. We can rearrange this formula to solve for the resistance, $R = \frac{V_{rms}^2}{P}$. Show more…
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