00:01
Hi, here in this given problem, average power used by the light bulb that is given as b, ab stands for average, average power that is 75 watt.
00:29
Rms voltage for the bulb that is 120 volt.
00:38
In the first part of the problem we have to find, resistance of the elevation of the aluminum of this bulb.
00:45
So using an expression for the average power consumed by the ac source and that is given as square of vrms divided by impedance and impedance of this circuit having bulb only that is r multiplied by power factor cos phi and we know for r only for resistance only this power factor comes out to be equal to 1.
01:20
So an expression for r will be square of vrms divided by average power.
01:29
Means this is square of 120 volt divided by 75 and it is calculated to be equal to 192 om.
01:41
Answer for the first part of this given problem here.
01:47
Then in the second part of this problem, now we have to find the maximum current passing through this circuit.
01:55
First of all, we find rms current using oms law that is given by the ratio of vrms and the resistance means this is 120 divided by 192...