00:01
In this question, we have this situation.
00:05
So a firefighter is laying down from a pole for four meters.
00:12
And then at the bottom, there's a platform.
00:17
And then this platform is supported by spring.
00:23
So in part a, we want to find the firefighter speed immediately before she collides with the platform.
00:29
Okay, so along the pole, there is a friction force of 300 newtons that resist the motion.
00:42
Okay, so for the free body diagram of the firefighter, we have the weight and we also have the friction acting on the firefighter.
00:53
So to find the speed, i'll be using work energy theorem.
01:06
Which says that the network done is the change in kinetic energy of the object.
01:14
So the network done for this firefighter would be m g minus friction times h and this is equal to half mv square.
01:27
And then the speed will just be 2 over m g minus f h squared okay putting in the numbers two times four which is the height and then 9 .8 minus 300 divided by 75 okay and then this is 6 .81 meters per second okay so this is the answer for part a then for part b we want to wants to find the maximum distance the spring is compressed.
02:24
Okay, so there is an elastic collision with the platform or perfectly inelastic collision with the platform.
02:45
So conservation of momentum equation would give us the firefighter times the mess of the firefighter times speed, which is this, 6 .81 is equal to the firefighter plus the platform, times the final speed.
03:15
So we get v -prime and then this is our world, actually final momentum, okay? i'm just going to leave it as that.
03:28
Then the spring is compressed after that...