00:01
Solution, step 1, from the given figure.
00:04
Since the steel strip is bent into a full circle, the total length of the strip is equal to the circumference of the circle.
00:12
Now, calculate the radius of curvature as follows, that length of the steel strip is equal to circumference of the circle, that is l equal to 2 pi p.
00:23
Here, l is the length of the steel, strip, and p is the radius of the curvature.
00:28
Now substitute 900 m m for l here by substituting we get 900 equal to 2 pi so for p we get p equal to 143 .24 m m m in bracket 1 m meter by thousand m which will be equal to 0 .14342424 m m m is the p now for the part a calculate the largest distance from the neutral axis as follows the sigma equal to ec by p so for c it will be c equal to p sigma by e here c is the largest distance from the neutral axis that is central distance sigma is the allowable stress and e is the modulus of elasticity now substitute 420 mp a 102d power 6 p a by 1 mp for sigma 0 .14324m for p and 200 gpa 10 to d power 6 pa by 1gpa 4e.
01:38
So here by substituting the value we get c equal to 0 .143 to 4 multiplied by in bracket 420 multiplied by 1020 the whole divided by 200 multiplied by 10 to the power 9 and from here we get it 3 .008 multiplied by 1020 minus 4m.
01:58
Now calculate the maximum thickness of the strip as follows the t equal to 2c here t is the the maximum thickness of the strip.
02:08
Now substitute 3 .008 multiply by 10204, 10 to power minus 4, 10 to power minus 4, c...