Question
A ball is thrown straight upward from the top of $a=$ building with an initial velocity of 32 feet per second. The equation $s=-16 t^{2}+32 t+48$ gives the height $s$ of the ball in feet $t$ seconds after it is thrown. Find the maximum height reached by the ball and the time it takes for the ball to hit the ground.
Step 1
Step 1: The given equation is a quadratic equation in the form of $s = at^2 + bt + c$, where $s$ is the height of the ball, $t$ is the time, $a = -16$, $b = 32$, and $c = 48$. Show more…
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