A battery has a terminal voltage of 12.0 V when no current flows. Its internal resistance is 2.0

step 1 So we have deliverable voltage equals the EMF of the battery minus I times the internal resistan

A battery has a terminal voltage of 12.0 V when no current...

A battery has a terminal voltage of $12.0 \mathrm{V}$ when no current flows. Its internal resistance is $2.0 \Omega .$ If a $1.0 \Omega$ resistor is connected across the battery terminals, what is the terminal voltage and what is the current through the $1.0 \Omega$ resistor?

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Ohm's Law

Ohm's Law states that the voltage across a resistor is directly proportional to the current flowing through it, with the constant of proportionality being the resistance (V = IR). This fundamental relationship is crucial in calculating current through circuit components and determining voltage drops across them.

Series Circuit Analysis

In a series circuit, resistances add up, which means the battery's internal resistance and the load resistance combine to form the total resistance in the circuit. This combined resistance is used to calculate the total current using Ohm's Law, and it allows for the analysis of individual voltage drops across each component.

Internal Resistance

Internal resistance is the inherent resistance within a power source that causes a voltage drop when current flows. It affects the effective voltage delivered to a load, as some of the electromotive force (emf) is lost across this internal component, reducing the terminal voltage during operation.

Terminal Voltage

Terminal voltage is the voltage measured across the output terminals of a power source when a load is connected. It is lower than the emf of the battery if internal resistance is present because the internal resistance causes a drop in voltage proportional to the current drawn.

Please give Ace some feedback