The factor of safety is given as 3.00, and the yield strength of the aluminum alloy is 250 MPa. We can calculate the allowable stress as follows:
$\sigma_{allowable} = \frac{\sigma_{y}}{Factor\,of\,Safety} = \frac{250\,\text{MPa}}{3.00} = 83.33\,\text{MPa}$
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