00:01
Like a refrigerator and air condition has as its purpose of removal of energy by heat from the cold reservoir, its ideal cop is cop of carnot, that is, cop of carnot, that is, cop of carnot is t -c divided by th -min -c -t -c, that is, equals to 280 -calvin divided by 20 .0 calving, and we get 14 .0.
00:26
First one is its actual cop is actual cop is 0 .400 multiply with 14 .0 is equal to 560 which is equals to modulus of qc divided by qh minus qc.
00:47
Here we get modulus of qc divided by delta t divided here in qh delta t minus minus qc divided by delta t.
01:04
And here we get now.
01:07
Here we can put the values and we will get 5 .60 into 10 .0 kilowatt is equal to 6 .602c divided by delta t.
01:22
And qc divided by delta t is equal to 8 .48 kilowatt.
01:30
This is part a.
01:32
Now in part b we have here in part b we have modulus of qh is equals to work engine plus modulus of qc.
01:46
Now work of engine divided by delta t is equals to modulus of qh by delta t that is minus qc by delta t that is equals to 10 kilowatt minus 8 .48 kilowatt minus 8 .48 kilowatt watt that is equals to 1 .52 kilowatt now in part c the air conditioner operates in a cycle so the entropy of the working fluid does not change the hot reservoir increases entropy by delta q h modulus of q h divided by ph that is equals to 10 .0 into 10 to power 3 jule per second multiply with 3600 seconds divided by 300 calvin that is equals to 1 .20 into 10 to power 5 goul per calvin...