00:01
Here in this question, we are going to find out the gauge pressure of the air in the tank.
00:10
So here we obtained the density of water at 20 degrees celsius from table a1 from the test scoop, which is given as row equal to 998 kilogram per mares, now we calculate the specific weight of water at 20 degrees celsius.
00:43
So specific rate of water at 20 degrees celsius is gamma equal to row multiply by g.
01:02
Now here is the acceleration due to gravity.
01:07
So we substitute 998, kilo -tube, per meter cube 4 multiplied by 9 .814g therefore we get gamma equal to 9790 newton per meter cube so this is the specific weight of motor at 20 degree celsius now on applying the principle of by nc to the system we get specific gravity multiplied by gamma v.
02:17
Equal to gamma x multiply by 0 .75v plus gamma air multiplied by 0 .25v now here sg is the specific gravity gamma is a specific weight of water, b is the volume, and gamma x is the specific weight of the cube.
02:49
Now we neglecting the hydraulic force due to air, therefore from above we get sg multiplier gamma multiplier v equal to gamma x multipla 0 .75v.
03:07
So from above we get gamma x equal to s g divided by 0 .75 multiply by gamma.
03:23
Now here we substitute 0 .6 for sg and 9790 newton per meter cube for gamma...