00:01
All right, we've got a boat traveling in the river.
00:08
So the boat travels at a speed v -sub b -w.
00:15
So let's say that the speed of the river, the river's flowing that way.
00:21
In order for the boat to go straight across, then the boat, just draw a boat here, a sailboat, would have to have.
00:31
To its velocity would have to be slightly downward vbw to counteract the flow of the river.
00:47
It might not even be slightly downward.
00:49
It might be way downward.
00:52
Okay.
00:56
So we need the time required to cross the river.
01:05
Okay.
01:05
Well, velocity is distance over time.
01:23
So, but we also want the y direction velocity to be zero.
01:39
So v sub y in the vbw.
01:59
In the y direction needs to equal vw.
02:10
So vbw, and then in the y direction would be sine theta.
02:22
This would be theta here, has to equal vw, where vw is the speed of the water.
02:31
So v sub -x is going to be x over t.
02:38
So vbw x.
02:45
So vbw, cosine theta, is going to be x over t.
02:56
So we need to solve for t.
03:03
Well, t from the upper equation is going to be x over vbw cosine theta.
03:20
Whoops.
03:24
Hey, where is it? i guess i want the wrong.
03:27
Ah, i want the wrong y.
03:29
Okay, vbw cosine theta.
03:33
So, okay, that's interesting.
03:53
But let's try rearranging this, the two equations, and solving for sine of theta and cosine theta.
04:05
Let's try that.
04:07
Sign of theta is vw over vbw.
04:16
And then the other one, cosine of theta would be x, over vbw t.
04:29
Okay, we know that the sine squared plus cosine squared equals 1.
04:41
So, vw over vbw squared squared plus x over vbwt squared squared equals 1.
04:59
Now i've been using x, but the book says that the width of the river is d.
05:06
So i'm going to change that to d.
05:11
Okay.
05:13
Now, now let's try solving for t...