00:01
Okay, so for question, we need to find out the momentum.
00:02
Momentum can be equal to gamma times mv.
00:04
Gamma is equal 1 over square rule, 1 minus v square over c squared, okay? gamma is the lawrence factor, m is the mass, v, the speed.
00:13
If we do some arrangement, we have p equal mv over square rule 1 minus v square over c squared.
00:19
And therefore, we know the mass is given as 12 .6 kilograms, and the speed was given at 0 .8, 7c.
00:29
We converted meter per second is 2 .61 times 10 to the power of 8 meter per second.
00:34
So now we can plug in the values.
00:37
We have p is equal to 12 .6 kilogram times 2 .61 times 10 to the power of 8 meter per second over square root 1 minus 2 .61 times 10 to the power of 8 meter per second over square root 1 minus 2 .61 second and n square and then over c square which is three times 10 to the power of 8 meter per second and n square and this will give us the momentum is about 6 .67 times 10 to the power of 9 kilogram times meter per second okay and for question b it was asking us the time to stop the body's motion.
01:58
So, well, we know the momentum is equal to force times time...