Question
A body is placed over an inclined plane of angle $\pi-\theta$. The angle between normal reaction and the weight of the body is(a) equal to the angle of friction(b) more than $\theta$(c) less than $\theta$(d) $\theta$
Step 1
We have a body placed on an inclined plane with an angle of inclination given by \(\pi - \theta\). We need to find the angle between the normal reaction force and the weight of the body. Show more…
Show all steps
Your feedback will help us improve your experience
Dheeraj Sharma and 55 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A box is placed on an inclined plane and has to be pushed down. The angle of inclination is (a) Equal to angle of friction (b) More than angle of friction (c) Equal to angle of repose (d) Less than angle of repose
A box of mass $8 \mathrm{~kg}$ is placed on a rough inclined plane of inclination $\theta$. Its downward motion can be prevented by applying an upward pull $F$ and it can be made to slide upwards by applying a force $2 F .$ The co-efficient of friction between the box and the inclined plane is (A) $\frac{1}{3} \tan \theta$ (B) $3 \tan \theta$ (C) $\frac{1}{2} \tan \theta$ (D) $2 \tan \theta$
A body is in equilibrium on a rough inclined plane under its own weight. If the angle of inclination of the inclined plane is $\alpha$ and the angle of friction is $\lambda$, then: (a) $\alpha>\lambda$ (b) $\alpha>\lambda_{2}$ (c) $\alpha=\lambda$ (d) $\alpha>\lambda$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD