A boy weighing 50 kg eats bananas. The energy content of...

A boy weighing $50 \mathrm{~kg}$ eats bananas. The energy content of banana is $1000 \mathrm{cal}$, if this energy is used to lift the boy from ground, then the height through which he is lifted : (a) $8.57 \mathrm{~m}$ (b) $10.57 \mathrm{~m}$ (c) $6.57 \mathrm{~m}$ (d) $5.57 \mathrm{~m}$

A boy weighing $50 \mathrm{~kg}$ eats bananas. The energy content of banana is $1000 \mathrm{cal}$, if this energy is used to lift the boy from ground, then the height through which he is lifted :
(a) $8.57 \mathrm{~m}$
(b) $10.57 \mathrm{~m}$
(c) $6.57 \mathrm{~m}$
(d) $5.57 \mathrm{~m}$

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Key Concepts

Conversion of Energy Units

This concept involves converting energy from one unit to another, such as from calories (a unit often used in nutritional contexts) to Joules (the SI unit for energy). Understanding this conversion is crucial when comparing or equating food energy to mechanical work or energy transfer in physics problems.

Gravitational Potential Energy

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, typically calculated using the formula E = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height above a reference level. This concept is key when determining how much work is required to raise an object to a given height.

Work-Energy Principle

This principle states that the work done on an object is equal to the change in its energy. In the context of lifting an object, the work performed against gravity is directly converted into gravitational potential energy. Recognizing this relationship helps in understanding energy transfer and conservation in mechanical systems.

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