00:01
Okay, so we have a buffer system here with dihydrogen phosphate and hydrogen phosphate.
00:12
We know that the ka for dihydrogen phosphate will need that, so that's going to be 6 .2 times 10 -9.
00:21
And they've told us the ratio of acid to base is 3 .0.
00:27
So let's see if we can find the ph of this buffer.
00:30
So the h -plus concentration equals k -a times the ratio, the concentration of the acid to the concentration of the base.
00:44
So we'll take our k -a, which is 6 .2 times 10 and negative 8, and we'll simply multiply by 3.
00:54
So 1 .86 times 10 and negative 7 molar.
01:00
So that's our h -plus concentration.
01:02
So if we take minus the log of that, we'll get our ph.
01:06
So our ph of this buffer is 6 .73.
01:13
And then what we're going to do is we're going to convert 15 % of our base to acid.
01:25
So we're going to end up with more acid and less base.
01:29
So hopefully we'll see this ph go down a little bit...