Question
(a) Calculate the chemical potential difference when intracellular $\left[\mathrm{Na}^{+}\right]=10 \mathrm{mM}$ and extracellular $\left[\mathrm{Na}^{+}\right]=150 \mathrm{mM}$ at $37^{\circ} \mathrm{C}$. (b) Whatwould the electrochemical potential be if the membrane potential were $-60 \mathrm{mV}$ (inside negative)?
Step 1
314 J/mol K), T is the temperature in Kelvin (310 K for 37°C), $[Na^{+}]_{out}$ is the extracellular sodium concentration (150 mM), and $[Na^{+}]_{in}$ is the intracellular sodium concentration (10 mM). Show more…
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Calculate the chemical potential difference when Na+ (sodium ion) concentration in the extracellular space is 150 mM and it is transported into the cells at 37"C. The intracellular Na+ concentration is 10 mM; the membrane potential is -60 mV (inside negative). R=8.314 J*K-1*mol-1. The value of ENa (Nernst potential for sodium) is calculated using the formula ENa = (RT/zF) * ln([Na+]out/[Na+]in), where R is the gas constant, T is the temperature in Kelvin, z is the valence of the ion, F is Faraday's constant, [Na+]out is the concentration of sodium ions outside the cell, and [Na+]in is the concentration of sodium ions inside the cell.
potential, the potential difference between the inside and outside of the cell membrane, is 70 mV. a. What is the change in electrical potential energy of the sodium ion when moving from inside the cell to outside the cell? b. How much work must be done on a sodium ion (Na+) to move it from inside the cell to outside the cell?
Consider a phospholipid vesicle containing $10 \mathrm{m} M \mathrm{Na}^{+}$ ions. The vesicle is bathed in a solution that contains $52 \mathrm{mM} \mathrm{Na}^{+}$ ions, and the electrical potential difference across the vesicle membrane $\Delta \psi=\psi_{\text {outside }}-\psi_{\text {inside }}=-30 \mathrm{mV} .$ What is the electrochemical potential at $25^{\circ} \mathrm{C}$ for $\mathrm{Na}^{+}$ ions?
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