Question
A car moves along a straight road in such a way that its velocity (in feet per second) at any time $t$ (in seconds) is given by$$v(t)=3 t \sqrt{16-t^{2}} \quad(0 \leq t \leq 4)$$Find the distance traveled by the car in the 4 sec from $t=0$ to $t=4$.
Step 1
We know that the distance traveled can be calculated by integrating the velocity function from $t=0$ to $t=4$. So, we need to evaluate the integral $\int_{0}^{4} v(t) dt$. Show more…
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