A car moves along a straight road in such a way that its velocity (in feet per second) at any time t (in seconds) is given by v(t) = 3t√(9-t^2) (0 ≤ t ≤ 3). Find the distance traveled by the car in the 3 seconds from t = 0 to t = 3.
Added by Theresa T.
Step 1
Step 1: Calculate the integral of the velocity function v(t) = 3t√(9-t^2) with respect to time t from 0 to 3. Show more…
Show all steps
Close
Your feedback will help us improve your experience
Rukhmani Jain and 71 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A car moves along a straight road in such a way that its velocity (in feet per second) at any time $t$ (in seconds) is given by $$v(t)=3 t \sqrt{16-t^{2}} \quad(0 \leq t \leq 4)$$ Find the distance traveled by the car in the 4 sec from $t=0$ to $t=4$.
Integration
Evaluating Definite Integrals
Erick L.
The velocity of a car (in feet per second) $t$ sec after starting from rest is given by the function $$f(t)=2 \sqrt{t} \quad(0 \leq t \leq 30)$$ Find the car's position, $s(t),$ at any time $t$. Assume that $s(0)=0$.
Antiderivatives and the Rules of Integration
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD