A car weighing $1400 \mathrm{~kg}$ is moving at a speed of $54 \mathrm{kmh}^{-1}$ up a hill when the motor stops. If it is just able to reach the destination which is at a height of $10 \mathrm{~m}$ above the point, then the work done against friction (negative of the work done by the friction) is (Take $g=10 \mathrm{~ms}^{-2}$ )
(a) $10 \mathrm{~kJ}$
(b) $15 \mathrm{~kJ}$
(c) $17.5 \mathrm{~kJ}$
(d) $25 \mathrm{~kJ}$