The potential energy function for a particle executing linear SHM is given by $V(x)=\frac{1}{2} k x^{2}$ where $k$ is the force constant of the oscillator. For $k=0.5 \mathrm{~N} / \mathrm{m}$, the graph of $V(x)$ versus $x$ is shown in the figure. A particle of total energy $E$ turns back when it reaches $x=\pm x_{m}$. If $V$ and $K$ indicate the $\mathrm{PE}$ and $\mathrm{KE}$ respectively of the particle at $x=\pm x_{m}$ then which of the following is correct? $\quad$ [NCERT Exemplar]
(a) $V=0, \bar{K}=\mathrm{E}$
(b) $V=\mathrm{E}, \bar{K}=0$
(c) $V<E, K=0$
(d) $V=0, K<0$