00:01
So we're given that a carbon resistor is going to be used as a thermometer.
00:10
And on a particular day, there is a temperature at 4 degrees celsius, which has a corresponding resistance of 217 .3 oms.
00:26
And i've just labeled these with w because the problem sounds on a winter day.
00:30
So just put w for winter and we're told that the reference temperature is 4 degrees celsius and they want to know on a different day when there is a when the resistor has a resistance of 215 .8 oms what is the temperature on that day so we can solve this problem if we have an equation that relates resistance to temperature, which we actually have one.
01:06
So equation 25 .12 gives you the resistance is a function of temperature is equal to some reference resistance, one plus alpha, which is some coefficient, and then the temperature.
01:32
And alpha can be found in table 25 point two.
01:40
So and this alpha will be alpha corresponding to carbon.
01:48
And it has units of inverse celsius.
01:56
So our goal here is to find r of t.
02:01
The resistance is a function of temperature, but we don't know this reference resistance.
02:10
So we know alpha, which we can find from the table and we know these two temperatures.
02:18
So using the information that we're given, let's find r of t, or rather let's find r not, because we have an r of t.
02:37
Okay, so at a particular temperature of 4 degrees celsius, we have rw, so that's equal to r0, 1 plus alpha t w minus t not but the reference temperature in d w are the same as we can see here right so this difference is zero so that tells us that are the reference the reference resistance is equal to r w which is already given to us as 217 .3 oms 7 .3 oms 7 .3...