00:01
31 .18.
00:02
So we have an oscillating lc circuit and the amplitudes of current and voltage are 7 .5 mliamps and 250 millibolds respectively and the capacitor has a value of 220 nanophares.
00:16
So we want to find some things, one of which is the period of the oscillation, the maximum energies stored in the inductor and the capacitor, the maximum rate of change of current, and the maximum rate of change of current, and the maximum rate of change of the inductor's energy.
00:40
So we know from the sort of general om's law for a capacitor that the amplitude of the voltage equals the amplitude of the current times the reactants, in this case of the capacitor.
01:00
So omega is going to be i over cb.
01:11
Now the period is two pi over omega and so then just evaluating that we find the period is 46 .1 microseconds.
01:50
So now the maximum energy the capacitor stores, and its electric field is one half cv squared.
02:03
And so if this is the amplitude, then that's the maximum value it will take.
02:10
And so this is 6 .88 times 10 to the negative 9th joules.
02:30
So now the maximum energy that the inductor stores, you know, in principle, you know, is l or i squared over over two which is a problem because we don't know what l is we know what c is and we know the frequency so we could figure it out but also we don't have to because of the conservation of energy and we know that it goes back and forth between all being in the capacitor and all being in the inductor that its maximum has to be the same and in fact this is the total energy in the system so let's start a new one.
03:30
So now we want to find the idt, or the maximum bidt.
03:38
So the voltage across the inductor is equal to l, the amplitude of that voltage, going to be didt maximum...