For Load 1, we have $S_1 = P_1 \angle \cos^{-1}(pf_1)$, where $P_1 = 240 \times 10^3$ and $pf_1 = 0.8$. This gives us $S_1 = 240 \times 10^3 \angle \cos^{-1}(0.8) = 240 \times 10^3 \angle 36.8699^\circ$. Converting this to rectangular form, we get $S_1 = 192 +
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