00:01
For this exercise, we have the compton scattering of a photon, so it scatters off an electron.
00:06
And the initial wavelength, the wavelength of the incident photon, is given by just lambda.
00:16
And the wavelength of the scattered photon is given by lambda prime, and its energy is given by e.
00:24
So this one here is the incident, and this one here is the scattered.
00:37
The first part of the exercise, question a, asks us for which value of theta, the angle theta of scattering, we're going to have the smallest value of the energy e.
00:53
So let's write here, compton's formula for lambda prime.
00:59
The scattered wavelength is going to be the initial wavelength, the incident wavelength, plus h -m -e -c, 1 minus cosine of theta.
01:13
And the energy of the scattered photon is going to be hc over lambda prime.
01:21
This is just planx formula.
01:23
So notice that we want the smallest energy, and the smallest energy is going to happen when we have the maximum wavelength.
01:35
And the maximum wavelength, we're going to have the maximum wavelength when 1 minus the cosine of theta, is maximum.
01:44
Okay, so we want 1 minus cosine of theta to be the largest number possible.
01:50
And this is going to happen when theta is 180 degrees.
01:54
And that's because when theta is 180 degrees, the cosine of theta is minimum.
02:00
So it's minus 1.
02:01
And this number here, 1 minus cosine of theta, is going to be 2.
02:09
Notice that cosine of theta cannot be any smaller than minus 1...