00:01
Here a copper plate is rotated between two silver for the same length and copper here.
00:09
So since it is being heated, so initial temperature is 0 degrees celsius and final temperature is 20 degrees of years after heating.
00:21
Now here we know that copper expands more than more than this we can also calculate we can also derive this idea from the linear extension of copper and steel because linear extension of copper is 18 and steel is 11 so here now there will be strength in the copper because copper will try to stretch more while still will try to stress will expect less so it will try to control the length of copper so copper and steel will apply force on each other laterally.
01:15
So here you can say net expansion.
01:27
So net expansion of copper will be equal to delta l which is in fact l final or i can say okay l this is about copper lc minus l0 equals to initial length l not linear coefficient of expansion of copper into changing temperature.
02:03
Delta is minor.
02:06
So that is due to the heating.
02:09
But that will not expand completely because it will apply force and it will stop it from expanding completely.
02:20
So that force it will try to stop it.
02:23
That is flyca.
02:31
That is that is in modulus of last is hitting y street.
02:36
So here f is 4 applied, l is the length, and that is for the copper, this is constant, and a is processed.
02:44
So that much length, that is deformation, this formula is for deformation...