00:01
In this problem, we're going to talk about time dilation.
00:02
So consider that we have a reference frame.
00:05
I'm going to call it the s reference frame.
00:09
And according to this reference frame, two events happen in the same place.
00:13
And the time between these two events is called tau.
00:17
Tau, i'm sorry, this is the proper time between the two events.
00:21
And it's special because it's the smallest possible time measured between these two events.
00:28
And you can recognize it because it's.
00:30
The time measure between the two events in the reference frame where the two events happen in the same place.
00:37
Now suppose that we have a second reference frame, i'm going to call it s prime, and in this reference frame the s reference frame is moving with a certain speed v.
00:50
Now notice that the two events don't happen in the same place anymore, they happen separately, and the time t between the two events is measured by the s prime reference ring is equal to tau times gamma, where gamma is 1 over the square root of 1 minus v squared over c squared.
01:11
Okay, what we have in our problem is a cosmic ray that travels a distance of 60 kilometers in a time of 400 microseconds according to an earth observer.
01:27
And our goal is to find how much time passes according to an observer at rest relative to the cosmic ray.
01:36
Well, first, notice that the speed of the cosmic ray relative to the earth is equal to d divided by t, so that's 60 kilometers, or 60 times 10 to the 3 meters, divided by 400 microseconds, or 400 times 10 to the minus 6 seconds, and this is equal to, v is equal to, 1 .5 times 10 to 8 meters per second...