00:01
So hello student now we are going to understand this question.
00:03
This is a hollow cylinder.
00:05
It is given something like this.
00:08
This is object of the figure and there is some thickness.
00:22
You can say the another cylinder is removed from inside.
00:27
This is the figure.
00:36
The internal radius which is given a small r and the external region which is given radius capital r.
00:44
So if you want to find the volume of this whole concrete so find the volume of the whole object and then remove the volume of the small one so first volume of whole cylinder i'm talking that just forget that we have removed something from inside so this is pi r is square and the radius of outer cylinder is capital r so pi r square and height is same for both and volume of removed cylinder so internal radius is smaller this is pi r square h now the volume of remaining part so volume of remaining part which is equal to total volume minus internal volume so, pi capital r square h minus pi small r square h.
02:06
So if you want, you can take pi h common.
02:10
So this is either this or actually we need to prove this only.
02:15
So it is we have proved like this...