A current density of 6.00 ×10^-13 A / m^2 exists in the atmosphere at a location where the elect

step 1 By Omslow we can write G is equal to sigma E. That is nothing but current density G. Sigma is th

A current density of 6.00 ×10^-13 A / m^2 exists in the...

A current density of $6.00 \times 10^{-13} \mathrm{A} / \mathrm{m}^{2}$ exists in the atmosphere at a location where the electric field is $100 \mathrm{V} / \mathrm{m}$ Calculate the electrical conductivity of the Earth's atmosphere in this region.

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Ohm's Law (Differential Form)

This form of Ohm's Law establishes a relationship at the microscopic level between the current density and the electric field in a material. It states that the current density (J) is proportional to the electric field (E) with the proportionality constant being the electrical conductivity (?), expressed simply as J = ?E.

Current Density

Current density is a measure of electric current per unit area of cross-section. It quantifies how much charge flows through a given area within a conductor and is typically expressed in amperes per square meter (A/m²).

Electric Field

The electric field represents the force per unit charge exerted on a test charge placed within the field. Measured in volts per meter (V/m), it drives the movement of charges in a material and is a key factor in determining the resulting current flow.

Electrical Conductivity

Electrical conductivity is a property that quantifies how efficiently a material can conduct electric current. It is defined as the ratio of the current density to the electric field (? = J/E) and indicates the ease with which charge carriers can move through the material.

Please give Ace some feedback