Question
A current density of $6.00 \times 10^{-13} \mathrm{~A} / \mathrm{m}^{2}$ exists in the atmosphere where the electric field (due to charged thunderclouds in the vicinity) is $100 \mathrm{~V} / \mathrm{m} .$ Calculate the electrical conductivity of the Earth's atmosphere in this region.
Step 1
00 \times 10^{-13} \, \mathrm{A/m}^{2}$ and the electric field $E = 100 \, \mathrm{V/m}$. We are asked to find the electrical conductivity $\sigma$. Show more…
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A current density of 6.00 $\times 10^{-13} \mathrm{A} / \mathrm{m}^{2}$ exists in the atmosphere at a location where the electric field is 100 $\mathrm{V} / \mathrm{m}$ . Calculate the electrical conductivity of the Earth's atmosphere in this region.
Earth's Atmosphere It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an altitude of $300 \mathrm{~m}$ the field has magnitude $60.0 \mathrm{~N} / \mathrm{C}$, at an altitude of $200 \mathrm{~m}$, the magnitude is $100 \mathrm{~N} / \mathrm{C}$. Find the net amount of charge contained in a cube $100 \mathrm{~m}$ on edge, with horizontal faces at altitudes of 200 and $300 \mathrm{~m}$. Neglect the curvature of Earth.
The Earth has an electric field of $150 . \mathrm{V} / \mathrm{m}$ near its surface. Find the electrical energy contained in each cubic meter of air near the surface.
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