00:01
Alright, so in this problem we're given a dehumidifier.
00:04
We're given some temperatures and we're asked about the water removed.
00:11
So i'm going to start by finding the coefficient of performance since we're given the temperatures necessary.
00:18
Remember, cop is equal to, let's remember, th over th minus tl.
00:32
Of course everything is in kelvin.
00:37
So our th value is 25 degrees celsius.
00:42
And if we add 273, we'll get 298 kelvin.
00:48
And the difference between the two is 17.
00:51
Dividing this out, you should get 17 .5.
00:56
So that's our coefficient of performance.
01:01
Now we're given, we're told that the way the heat is removed by the refrigerator coil mostly comes from condensation.
01:11
So that tells us that q is mostly in the form of ml, and that's how we're going to do our estimate.
01:17
So one other piece of information we're given in the problem is that the dehumidifier does work at 600 watts...