Question
(a) Determine the average magnitude of the $\vec{E}$ field across a body cell membrane. A $0.07-\mathrm{V}$ potential difference exists from one side to the other and the membrane is $7.5 \times 10^{-9}$ $\mathrm{m}$ thick. (b) Determine the magnitude of the electrical force on a sodium ion (charge +e) in the membrane. Assume that the dielectric constant is 1.0(it is actually somewhat larger).
Step 1
In this case, the potential difference is $0.07$ V and the distance is $7.5 \times 10^{-9}$ m. So, the electric field $\vec{E}$ is given by: \[ \vec{E} = \frac{V}{d} \] where $V$ is the potential difference and $d$ is the distance. Show more…
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