00:01
And so this is just asking us to draw a free body diagram of this skier.
00:05
So we represent the skier with the block.
00:09
So we have the downward force due to gravity.
00:16
Okay, we have an angle of 22 degrees.
00:20
We have a normal force that's going to be counter to the component of gravity that's perpendicular to the slope.
00:33
So we have it we have two components to the gravity.
00:36
So if we think about the force due to gravity as a hypotenuse, then this angle would be 22 degrees.
00:48
And if we want to know the component of the force perpendicular to the incline, we would do fg times cosine of 22 degrees.
01:04
And that would be equal and opposite to the normal force in magnitude.
01:14
Okay, and then the parallel force due to gravity would be the fg times sine of 22.
01:25
And that's going to be like the applied force in this case.
01:31
So f .a, we go here, we have fn, and we have this opposite component of our normal force.
01:39
And that's just due to the gravity...