(a) Escriba una ecuación de la reacción en la que H2 C6 O5 H7^-(a c) actúa como base en H2 O(l).

(a) Escriba una ecuación de la reacción en la que H2 C6 O5...

(a) Escriba una ecuación de la reacción en la que $\mathrm{H}_2 \mathrm{C}_6 \mathrm{O}_5 \mathrm{H}_7^{-}(a c)$ actúa como base en $\mathrm{H}_2 \mathrm{O}(l)$. (b) Escriba una ecuación de la reacción en la que $\mathrm{H}_2 \mathrm{C}_6 \mathrm{O}_3 \mathrm{H}_7{ }^{-}(a c)$ actúa como ácido en $\mathrm{H}_2 \mathrm{O}(l)$. (c) 2 Cuál es el ácido conjugado de $\mathrm{H}_2 \mathrm{C}_6 \mathrm{O}_5 \mathrm{H}_7^{-}$? ${ }_2$ Cuál es su base conjugada?

Key Concepts

Conjugate acid-base pairs

A conjugate acid-base pair consists of two species that transform into one another by the loss or gain of a proton. When an acid donates a proton, it becomes its conjugate base; conversely, when a base accepts a proton, it becomes its conjugate acid. Understanding this relationship is crucial for predicting the outcome of acid-base reactions and for writing correct chemical equations.

Proton transfer mechanism

The proton transfer mechanism is central to acid-base chemistry. This mechanism details how a proton is transferred from an acid to a base in a chemical reaction. It is a key concept in understanding how acids and bases behave in solution and how equilibrium is established between various species in a reaction.

Acid-base reactions

Acid-base reactions involve the transfer of protons (H?) between species. In aqueous solutions, this process is often described using the Brønsted-Lowry theory, where acids are proton donors and bases are proton acceptors. Writing the corresponding reaction equations requires identifying which molecule donates a proton and which one accepts it, as well as accounting for water's role as a solvent and participant in the reaction.

Transcript

00:01 All right, today we're doing chapter 16, problem 20 from chemistry, essential science, 14th edition by brown.

00:09 So this question is asking us to use h2c6, h705 minus, as our base in adding water to it, and it's also doing the same thing, but acting as an acid, and then it's wanting us to write the equation for those two different conditions, and then telling us to write its conjugate acid and a conjugate base of.

00:31 That molecule.

00:33 And when you read through this question, you first think that should pop out is that it's this conjugate acid and conjugate base.

00:41 The only type of acid and base that has a conjugate's is the bronchon lary.

00:46 And since we know that, we can easily be able to write these equations, knowing how a bronch and lary acid and base react.

00:55 So bronzum lary acid is an h plus donor, where a base is an h plus acceptor.

01:02 So for a, it's asking us to write it as the molecule is reacting as a base in h2o.

01:11 So we have h2c6 h705 minus plus h2o.

01:32 And since we know that they want this to act as the base, and then this is going to be the acid in the definitions that we just read about that the acid donates a hydrogen.

01:50 We know that this has to accept the hydrogen.

01:53 So therefore, we're going to have the h3c6h705.

02:02 And since we added a positive proton to a negative, it now becomes neutral.

02:12 And then we then took away a hydrogen from the h2o and now have an oh minus.

02:20 And then this is an aqueous and this is aqueous.

02:26 And that would be our equation for part one.

02:30 So for b, it now acts as to use that same starting reagent in water...