00:03
Hey guys let's do problem 30 in this problem we need to calculate the concentration of benzene in the original room temperature at three collection times let's do that the condition one is when the sample is collected we need to calculate the concentration of benzin in the collection period from ideal gas law we know pv is equal to in r t or the number of moles is equal to pressure 1 divided by v or temperature 1.
00:42
Given the pressure is, pressure of the system is 99 kilo -pascal, let's convert it to atm, which is 0 .977 atm, and the temperature is 33 degrees celsius.
01:05
Let's convert it to kelvin scale, which is 300 ,000.
01:12
Kelvin therefore the number of moles is 0 .977 atmospheric pressure multiplied by 2 liter which is given gas constant is 0 .08 to 1 liter 80m mole inverse 1 kelvin inverse 1 and the temperature is 306 kelvin therefore the number of moons at condition 1 is 0 .078 moles and this is equal to the number equal to the sum of number of moles of air and the number of moles of benzene therefore 0 .078 is equal to in air plus in benzene now let's go to condition 2 when helium is added and in this case pressure is 500 kilo -pascal let's convert 8m.
02:33
Atmosphere pressure which is 4 .93 atmospheric pressure.
02:39
The temperature was 33 degrees celsius therefore it is 306 kelvin therefore the number of moles is 4 .9303m.
03:02
Multiplied 2 liter divided by 0 .081 liter 1 inverse 1, kelvin inverse 1 multiplied by 306 kelvin, which is equal to 0 .393 mole.
03:19
Therefore, the number of moles at condition 2 is 0 .0 .0 .393 mole.
03:31
And this number is the sum of the number of the number of mole of air, number of mole of benzene, and number of mole of helium.
03:41
Now we need to go to condition 3 when the gas is fed to gas chromatograph.
04:06
Let's go to condition 3 when gas is fed to gas chromatograph.
04:37
In this situation, pressure is 400 kilo -pascal.
04:43
Let's convert it to atmospheric pressure, which is 3 .94 atmospheric pressure.
04:52
The temperature is 23 degrees celsius which is 296 kelvin therefore the number of moles is 3 .93 atmospheric pressure multiplied by 2 liter divided by 0 .08 to 1 multiply by 296 kelvin and the number of moles we get is 0 .325 moles therefore the number of moles at condition 3 is 0 .325 moles which is equal to the entrance of number which is equal to the number of moles at condition 3 and number of months of gas injected therefore in 3 is the subtraction of number of moles of gas at condition 2 minus the number of moles of gas injected or 0 .325 mol is equal to n2 and we know n2 is in air number of months of air number of months of benzene and number of months of helium now if we subtract equation two equation three from equation two then what we will get is number of during injection number of months of gas injected is equal to 0 .393 minus 0 .325 moles which is 0 .068 mole therefore the number of months of benzene is equal to number of moles in the benzene gas chromatograph multiply by number of moons during condition 2 divided by number of months number of moons of gas injected or we can write or we can write that number of moons of benzene is equal to mass of benzene in the gas chromatograph divided by molar mass of benzene multiplied by number of moons during condition 2 divided by number of months in the injected gas the molar mass of benzene is 78 gram per moon and the number of moles during condition 2 is 0 .393 mole and number of moles of gas injected is 0 .068 moles...