Question
(a) Find the differential $ dy $ and (b) evaluate $ dy $ for the given values of $ x $ and $ dx. $$ y = \frac {x + 1}{x - 1}, x = 2, dx = 0.05 $
Step 1
We can use the quotient rule for differentiation, which states that the derivative of $ \frac {f(x)}{g(x)} $ is $ \frac {f'(x)g(x) - f(x)g'(x)}{[g(x)]^2} $. Show more…
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(a) Find the differential dy y = ex/2 dy = (b) Evaluate dy for the given values of x and dx. x = 0, dx = 0.05 dy =
(a) Find the differential dy. y = ex/2 dy = (b) Evaluate dy for the given values of x and dx. x = 0, dx = 0.05 dy =
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