00:01
For the first part of this exercise, we have to find the first four energy levels of the doubly ionized lithium atom.
00:10
So let's do it.
00:12
Remember that the nth energy level of a hydrogen -like atom is given by minus z squared.
00:20
Z is the atomic number over n squared times 13 .6 electron volts.
00:29
And it's legitimate to consider the doubly ionized lithium as hydrogen -like atom, because since it's been doubly ionized, it has only one electron orbiting the nucleus.
00:45
And so let's also remember that the lithium has an atomic number of three, so that the energy levels of the lithium can be written as minus three squared, which is 9 times 13 .6 electron volts over n squared and 9 times 13 .6 is 122 .4 over n squared.
01:16
So now we are in a position to calculate the first four levels.
01:21
Okay.
01:23
The first level and equals one.
01:25
So the first level is just minus 122 .4 electron volts.
01:31
The second level you're going to have minus 122 .4 over 4, and that is minus 30 .6 electron volts.
01:48
For the third level, we're going to have minus 122 .4 over 9, and that is minus 13 .6, and final, electon volts, of course.
02:04
And finally, for the fourth, for fourth, for fourth, energy level we're going to have minus 122 .4 over 16, and this is minus 7 .165 electron volts.
02:21
So this is the question to the answer to question a.
02:25
Question b asks us to calculate the energy of the photons emitted in each transition between these levels.
02:36
So let's start by the transition from the second level to the first one.
02:41
The photon, the emitted photon, it's going to have an energy that is the difference between the energy of the second level and the energy of the first one.
02:53
And this is going to be minus 30 .6 plus 122 .4, and this is 91 .8, electron volts.
03:06
From the third to the second, we're going to have e3 minus e2, and this is 17, electron volts...