(a) The two 6.00 Ω resistors are in parallel, so their equivalent resistance is:
$R_{1} = \frac{1}{\frac{1}{6} + \frac{1}{6}} = 3.00 \Omega$
Now, we have a 3.00 Ω resistor in series with a 4.00 Ω resistor, so their equivalent resistance is:
$R_{2} = 3.00 \Omega
Show more…