00:01
So for this, we want to find the gradient vector.
00:05
And to do this, we want to find the gradient of f.
00:08
So we know that the gradient is the partial derivative of x, partial derivative of x, partial derivative of y, partial derivative of z, and it's the vector.
00:18
So this is going to be the gradient of f, and it will equal, we want to take the partial derivative with respect to x first.
00:28
And that's going to ultimately give us y cubed z e to the x y z then we take the partial derivative with respect to y and get 2 y e to the x y z and then um that's plus x y squared z e to the x y z and lastly we get x y cubed e to the x y z that right there is our gradient of f a vector we could simplify this further by factoring out an e to the xyz when we do that we'll just pull this out right here that will be our final answer for the gradient of f then for part b what we're wanting to do is evaluate the gradient at point p we know that that p is 0, 1, negative 1, trying to x, y, and z respectively.
01:55
So what we'll end up getting for f, the gradient of f of 0, 1, negative 1 is going to be 1 cubed.
02:11
That's just 1 times 1 times e to the 0, which is just 1.
02:19
Oh, and this is going to be a negative one.
02:22
Then right here, we get e to the zero, which is just one times two times one plus zero times a bunch of things.
02:37
So that's just two times one.
02:40
Let's clear this up.
02:41
So this is going to be two, and this will be a negative one right here...