00:01
We have the function cosine x plus square root of y equals 5.
00:07
And we want to find y prime in two different ways and check that they agree with each other.
00:16
So the first way is by implicit differentiation, which means that i'm going to take the derivative of both sides of this equation with respect to x, keeping in mind that y is a function of x.
00:28
So first we start with on the left side cosine x the derivative of cosine x is minus sine x plus.
00:38
Now i have the square root of y, which is really y to the one -half.
00:45
So by the chain rule, i first take the derivative of the outside function, which is raising an input to the power of one -half.
00:52
So by the power rule, i get that the derivative is one -half y to the minus one -half.
00:57
Then i have to multiply by the derivative of the inside function, which is y, and the derivative of that is y prime.
01:05
And this equals the derivative of 5 with respect to x, which is 0.
01:09
So now i am going to isolate the term that has y prime as a factor.
01:24
So 1 half y to the minus 1 half times y prime equals sine x.
01:29
And this is really another way to write this is y prime divided by two square root of y equals sine x and now it might be a little easier to see how to solve for y prime sine x or two sine x times square root of y now the second way that we can find y prime is first by solving for y from the original equation.
02:07
So we can move the cosine x over to the right.
02:11
So we get 5 minus cosine x.
02:13
And we can square everything and get, let's see, 25 minus 10 cosine x plus cosine squared x...