00:01
Okay, first we're going to take the derivative explicitly, implicitly, and then we're going to solve it for y explicitly, and then take his derivative.
00:10
Okay, remember, when you take the derivative of x, you get one, but when you take the derivative of y, you get y prime.
00:20
Okay, so 5x squared, its derivative would be 10x times the derivative of x, which is one, minus the derivative of y cube would be 3y squared, times 3 .y squared, times 3.
00:31
The derivative of y, which is y prime, and then the derivative of seven, which is zero.
00:39
So minus three y squared y prime equals negative 10x.
00:45
So right prime 10x over three y squared.
00:53
Okay, now i'm going to solve the equation for y, so i have minus y cubed equals seven minus five x squared.
01:03
Okay, and multiply by negative one here...