00:01
For this problem on the topic of motion in two dimensions.
00:04
We are told that a fish that is swimming in a horizontal plane has a given initial velocity at a point in the ocean where its position is relative to a certain rock and that position is given.
00:16
The fish swims with constant acceleration for 20 seconds until it reaches a given final velocity and we want to calculate the components of the acceleration, the direction of the acceleration with respect to unit vector i and the direction that is moving if it maintains constant acceleration.
00:37
So firstly, the initial velocity v -i, we can see is 4 times unit vector i plus 1j, and that's meters per second.
00:57
Its final velocity is given as v, and v is equal to, and so this is v as a function of time, where time t is 20 seconds, and this is given as 20 i minus 5j.
01:24
And this again is in meters a second.
01:29
So firstly, we need to calculate the acceleration.
01:33
So the x component of acceleration, a x, is the rate of change of the x component of the fission's velocity, delta vx, delta t.
01:44
And this is 20 minus 4 looking at only the components along the i direction divided by the change in time, which is 20 seconds.
02:03
So our final answer here will be in meters per square second, which we know is the si unit for acceleration, and we get this to be 0 .8 meters per square second.
02:19
Similarly, the y component of the acceleration is delta v y by delta t.
02:28
And so this is minus 5 minus 1 over the change in time is again 20, and that's in meters per square second, which gives us the y component of acceleration to be minus 0 .3 meters per square second.
02:52
So we found the acceleration of the fish at time t is equal to 20 seconds.
03:03
For the next part of the problem, we want to find the direction of the acceleration with respect to unit vector i...