Question
A flow of 1 lom/s argon at 540 R and another flow of $1 \mathrm{lbm} / \mathrm{s} \mathrm{CO}_{2}$ at $2800 \mathrm{R}$, both at $20 \mathrm{psia}$ are mixed without any heat transfer. What is the exit $T, P ?$
Step 1
In this case, there is no heat transfer, so the equation simplifies to $\Delta U = 0$. This means that the initial enthalpy of the argon and CO2 must equal the final enthalpy of the mixture. Show more…
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